Base | Representation |
---|---|
bin | 1001001101110101001110… |
… | …0101001101001000010111 |
3 | 1022212201122020012020220020 |
4 | 2103131103211031020113 |
5 | 2312010323402111203 |
6 | 33315050332440223 |
7 | 2064046613541513 |
oct | 223352345151027 |
9 | 38781566166806 |
10 | 10133230113303 |
11 | 325752a254080 |
12 | 1177a7a319073 |
13 | 5867372b32ab |
14 | 2706455c1143 |
15 | 1288c6652153 |
hex | 9375394d217 |
10133230113303 has 32 divisors (see below), whose sum is σ = 15268386470400. Its totient is φ = 5924241523200.
The previous prime is 10133230113289. The next prime is 10133230113329. The reversal of 10133230113303 is 30331103233101.
10133230113303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10133230113303 - 25 = 10133230113271 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10133230113703) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 41955163 + ... + 42195996.
It is an arithmetic number, because the mean of its divisors is an integer number (477137077200).
Almost surely, 210133230113303 is an apocalyptic number.
10133230113303 is a deficient number, since it is larger than the sum of its proper divisors (5135156357097).
10133230113303 is a wasteful number, since it uses less digits than its factorization.
10133230113303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84151303.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 10133230113303 its reverse (30331103233101), we get a palindrome (40464333346404).
The spelling of 10133230113303 in words is "ten trillion, one hundred thirty-three billion, two hundred thirty million, one hundred thirteen thousand, three hundred three".
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