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1013331001213 is a prime number
BaseRepresentation
bin11101011111011110011…
…10111111111101111101
310120212120210001110020201
432233233032333331331
5113100300214014323
62053303504043501
7133132200251536
oct16575716777575
93525523043221
101013331001213
11360829a29473
12144482603591
1374731100c3b
143708cb3568d
151b55bc9c8ad
hexebef3bff7d

1013331001213 has 2 divisors, whose sum is σ = 1013331001214. Its totient is φ = 1013331001212.

The previous prime is 1013331001157. The next prime is 1013331001219. The reversal of 1013331001213 is 3121001333101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 937726899769 + 75604101444 = 968363^2 + 274962^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1013331001213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1013331001219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506665500606 + 506665500607.

It is an arithmetic number, because the mean of its divisors is an integer number (506665500607).

Almost surely, 21013331001213 is an apocalyptic number.

It is an amenable number.

1013331001213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013331001213 is an equidigital number, since it uses as much as digits as its factorization.

1013331001213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1013331001213 its reverse (3121001333101), we get a palindrome (4134332334314).

The spelling of 1013331001213 in words is "one trillion, thirteen billion, three hundred thirty-one million, one thousand, two hundred thirteen".