101333112120 has 192 divisors, whose sum is σ = 346484960640. Its totient is φ = 25650432000.

The previous prime is 101333112119. The next prime is 101333112137. The reversal of 101333112120 is 21211333101.

101333112120 is a `hidden beast` number, since 10 + 133 + 311 + 212 + 0 = 666.

It is a super-2 number, since 2×101333112120² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 101333112093 and 101333112102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 453345 + ... + 638895.

It is an arithmetic number, because the mean of its divisors is an integer number (1804609170).

Almost surely, 2^101333112120 is an apocalyptic number.

101333112120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 101333112120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (173242480320).

101333112120 is an abundant number, since it is smaller than the sum of its proper divisors (245151848520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101333112120 is a wasteful number, since it uses less digits than its factorization.

101333112120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 185646 (or 185639 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 101333112120 its reverse (21211333101), we get a palindrome (122544445221).

The spelling of 101333112120 in words is "one hundred one billion, three hundred thirty-three million, one hundred twelve thousand, one hundred twenty".