10133351411 has 2 divisors, whose sum is σ = 10133351412. Its totient is φ = 10133351410.

The previous prime is 10133351407. The next prime is 10133351413. The reversal of 10133351411 is 11415333101.

It is a strong prime.

It is an emirp because it is prime and its reverse (11415333101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10133351411 - 2² = 10133351407 is a prime.

Together with 10133351413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10133351413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066675705 + 5066675706.

It is an arithmetic number, because the mean of its divisors is an integer number (5066675706).

Almost surely, 2^10133351411 is an apocalyptic number.

10133351411 is a deficient number, since it is larger than the sum of its proper divisors (1).

10133351411 is an equidigital number, since it uses as much as digits as its factorization.

10133351411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 10133351411 its reverse (11415333101), we get a palindrome (21548684512).

The spelling of 10133351411 in words is "ten billion, one hundred thirty-three million, three hundred fifty-one thousand, four hundred eleven".