Base | Representation |
---|---|
bin | 10010111000000000… |
… | …10010000101011001 |
3 | 222011012222202220011 |
4 | 21130000102011121 |
5 | 131223134400122 |
6 | 4353312201521 |
7 | 506055302221 |
oct | 113400220531 |
9 | 28135882804 |
10 | 10133512537 |
11 | 4330115a55 |
12 | 1b698392a1 |
13 | c56565985 |
14 | 6c1b99081 |
15 | 3e4982377 |
hex | 25c012159 |
10133512537 has 2 divisors, whose sum is σ = 10133512538. Its totient is φ = 10133512536.
The previous prime is 10133512489. The next prime is 10133512553. The reversal of 10133512537 is 73521533101.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9173999961 + 959512576 = 95781^2 + 30976^2 .
It is a cyclic number.
It is not a de Polignac number, because 10133512537 - 211 = 10133510489 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10133512499 and 10133512508.
It is not a weakly prime, because it can be changed into another prime (10133518537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066756268 + 5066756269.
It is an arithmetic number, because the mean of its divisors is an integer number (5066756269).
Almost surely, 210133512537 is an apocalyptic number.
It is an amenable number.
10133512537 is a deficient number, since it is larger than the sum of its proper divisors (1).
10133512537 is an equidigital number, since it uses as much as digits as its factorization.
10133512537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9450, while the sum is 31.
The spelling of 10133512537 in words is "ten billion, one hundred thirty-three million, five hundred twelve thousand, five hundred thirty-seven".
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