Base | Representation |
---|---|
bin | 101111001100001110… |
… | …1100011101111001101 |
3 | 100200120201002202212122 |
4 | 1132120131203233031 |
5 | 3130022041230242 |
6 | 114320025342325 |
7 | 10215231630164 |
oct | 1363035435715 |
9 | 320521082778 |
10 | 101342133197 |
11 | 39a84aa0698 |
12 | 177833379a5 |
13 | 97308aa1b6 |
14 | 4c953cc3db |
15 | 2981e9dad2 |
hex | 1798763bcd |
101342133197 has 2 divisors, whose sum is σ = 101342133198. Its totient is φ = 101342133196.
The previous prime is 101342133187. The next prime is 101342133209. The reversal of 101342133197 is 791331243101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 90945068041 + 10397065156 = 301571^2 + 101966^2 .
It is a cyclic number.
It is not a de Polignac number, because 101342133197 - 210 = 101342132173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101342133187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50671066598 + 50671066599.
It is an arithmetic number, because the mean of its divisors is an integer number (50671066599).
Almost surely, 2101342133197 is an apocalyptic number.
It is an amenable number.
101342133197 is a deficient number, since it is larger than the sum of its proper divisors (1).
101342133197 is an equidigital number, since it uses as much as digits as its factorization.
101342133197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 35.
Adding to 101342133197 its reverse (791331243101), we get a palindrome (892673376298).
The spelling of 101342133197 in words is "one hundred one billion, three hundred forty-two million, one hundred thirty-three thousand, one hundred ninety-seven".
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