Base | Representation |
---|---|
bin | 101111001100010000… |
… | …1101110000100110001 |
3 | 100200120210011012022221 |
4 | 1132120201232010301 |
5 | 3130022331132423 |
6 | 114320105001041 |
7 | 10215244122535 |
oct | 1363041560461 |
9 | 320523135287 |
10 | 101343224113 |
11 | 39a8567627a |
12 | 17783783181 |
13 | 9730b9c901 |
14 | 4c955d3bc5 |
15 | 2982116e5d |
hex | 179886e131 |
101343224113 has 2 divisors, whose sum is σ = 101343224114. Its totient is φ = 101343224112.
The previous prime is 101343224107. The next prime is 101343224137. The reversal of 101343224113 is 311422343101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96380444304 + 4962779809 = 310452^2 + 70447^2 .
It is a cyclic number.
It is not a de Polignac number, because 101343224113 - 229 = 100806353201 is a prime.
It is not a weakly prime, because it can be changed into another prime (101343224713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50671612056 + 50671612057.
It is an arithmetic number, because the mean of its divisors is an integer number (50671612057).
Almost surely, 2101343224113 is an apocalyptic number.
It is an amenable number.
101343224113 is a deficient number, since it is larger than the sum of its proper divisors (1).
101343224113 is an equidigital number, since it uses as much as digits as its factorization.
101343224113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 101343224113 its reverse (311422343101), we get a palindrome (412765567214).
The spelling of 101343224113 in words is "one hundred one billion, three hundred forty-three million, two hundred twenty-four thousand, one hundred thirteen".
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