1013441212181 has 2 divisors, whose sum is σ = 1013441212182. Its totient is φ = 1013441212180.

The previous prime is 1013441212159. The next prime is 1013441212193. The reversal of 1013441212181 is 1812121443101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1004823803281 + 8617408900 = 1002409^2 + 92830^2 .

It is a cyclic number.

It is not a de Polignac number, because 1013441212181 - 2⁶ = 1013441212117 is a prime.

It is a super-4 number, since 4×1013441212181⁴ (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1013441212111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506720606090 + 506720606091.

It is an arithmetic number, because the mean of its divisors is an integer number (506720606091).

Almost surely, 2^{1013441212181} is an apocalyptic number.

It is an amenable number.

1013441212181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013441212181 is an equidigital number, since it uses as much as digits as its factorization.

1013441212181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 29.

Adding to 1013441212181 its reverse (1812121443101), we get a palindrome (2825562655282).

The spelling of 1013441212181 in words is "one trillion, thirteen billion, four hundred forty-one million, two hundred twelve thousand, one hundred eighty-one".