Base | Representation |
---|---|
bin | 11101011111101100110… |
… | …00111101100001111001 |
3 | 10120212220010221201120202 |
4 | 32233312120331201321 |
5 | 113101021432200202 |
6 | 2053323433131545 |
7 | 133135155550343 |
oct | 16576630754171 |
9 | 3525803851522 |
10 | 1013451053177 |
11 | 360890776272 |
12 | 1444b6859bb5 |
13 | 7474cc456c4 |
14 | 370a0a66293 |
15 | 1b5675b3802 |
hex | ebf663d879 |
1013451053177 has 2 divisors, whose sum is σ = 1013451053178. Its totient is φ = 1013451053176.
The previous prime is 1013451053171. The next prime is 1013451053203. The reversal of 1013451053177 is 7713501543101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 605687071081 + 407763982096 = 778259^2 + 638564^2 .
It is a cyclic number.
It is not a de Polignac number, because 1013451053177 - 26 = 1013451053113 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1013451053177.
It is not a weakly prime, because it can be changed into another prime (1013451053171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506725526588 + 506725526589.
It is an arithmetic number, because the mean of its divisors is an integer number (506725526589).
Almost surely, 21013451053177 is an apocalyptic number.
It is an amenable number.
1013451053177 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013451053177 is an equidigital number, since it uses as much as digits as its factorization.
1013451053177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 44100, while the sum is 38.
Adding to 1013451053177 its reverse (7713501543101), we get a palindrome (8726952596278).
The spelling of 1013451053177 in words is "one trillion, thirteen billion, four hundred fifty-one million, fifty-three thousand, one hundred seventy-seven".
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