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1014000211214 = 22771830325291
BaseRepresentation
bin11101100000101110001…
…11110101010100001110
310120221022102021211210022
432300113013311110032
5113103133023224324
62053454131342142
7133154604404234
oct16602707652416
93527272254708
101014000211214
11361042758891
1214462a751952
137480994c8a3
1437113976954
151b59a8dc05e
hexec171f550e

1014000211214 has 8 divisors (see below), whose sum is σ = 1526491293528. Its totient is φ = 505169780040.

The previous prime is 1014000211187. The next prime is 1014000211243. The reversal of 1014000211214 is 4121120004101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×10140002112142 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1014000211192 and 1014000211201.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 915162092 + ... + 915163199.

It is an arithmetic number, because the mean of its divisors is an integer number (190811411691).

Almost surely, 21014000211214 is an apocalyptic number.

1014000211214 is a deficient number, since it is larger than the sum of its proper divisors (512491082314).

1014000211214 is a wasteful number, since it uses less digits than its factorization.

1014000211214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1830325570.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 1014000211214 its reverse (4121120004101), we get a palindrome (5135120215315).

The spelling of 1014000211214 in words is "one trillion, fourteen billion, two hundred eleven thousand, two hundred fourteen".

Divisors: 1 2 277 554 1830325291 3660650582 507000105607 1014000211214