1014000214 has 4 divisors (see below), whose sum is σ = 1521000324. Its totient is φ = 507000106.

The previous prime is 1014000199. The next prime is 1014000257. The reversal of 1014000214 is 4120004101.

1014000214 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4120004101 = 1063 ⋅3875827.

It is a junction number, because it is equal to n+sod(n) for n = 1014000194 and 1014000203.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 253500052 + ... + 253500055.

It is an arithmetic number, because the mean of its divisors is an integer number (380250081).

Almost surely, 2^1014000214 is an apocalyptic number.

1014000214 is a deficient number, since it is larger than the sum of its proper divisors (507000110).

1014000214 is an equidigital number, since it uses as much as digits as its factorization.

1014000214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 507000109.

The product of its (nonzero) digits is 32, while the sum is 13.

The square root of 1014000214 is about 31843.3700163786. The cubic root of 1014000214 is about 1004.6451273820.

Adding to 1014000214 its reverse (4120004101), we get a palindrome (5134004315).

The spelling of 1014000214 in words is "one billion, fourteen million, two hundred fourteen", and thus it is an aban number.