Base | Representation |
---|---|
bin | 10010111000110010… |
… | …00011000101011111 |
3 | 222011200012121110202 |
4 | 21130121003011133 |
5 | 131231320122303 |
6 | 4354103254115 |
7 | 506164421633 |
oct | 113431030537 |
9 | 28150177422 |
10 | 10140004703 |
11 | 433384a684 |
12 | 1b6ba4a33b |
13 | c579c99aa |
14 | 6c29a8dc3 |
15 | 3e5315c88 |
hex | 25c64315f |
10140004703 has 2 divisors, whose sum is σ = 10140004704. Its totient is φ = 10140004702.
The previous prime is 10140004691. The next prime is 10140004753. The reversal of 10140004703 is 30740004101.
10140004703 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10140004703 - 214 = 10139988319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10140004753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5070002351 + 5070002352.
It is an arithmetic number, because the mean of its divisors is an integer number (5070002352).
Almost surely, 210140004703 is an apocalyptic number.
10140004703 is a deficient number, since it is larger than the sum of its proper divisors (1).
10140004703 is an equidigital number, since it uses as much as digits as its factorization.
10140004703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 20.
Adding to 10140004703 its reverse (30740004101), we get a palindrome (40880008804).
The spelling of 10140004703 in words is "ten billion, one hundred forty million, four thousand, seven hundred three".
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