10140134117 has 2 divisors, whose sum is σ = 10140134118. Its totient is φ = 10140134116.

The previous prime is 10140134087. The next prime is 10140134129. The reversal of 10140134117 is 71143104101.

10140134117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5959994401 + 4180139716 = 77201^2 + 64654^2 .

It is a cyclic number.

It is not a de Polignac number, because 10140134117 - 2²² = 10135939813 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10140134092 and 10140134101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10140134167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5070067058 + 5070067059.

It is an arithmetic number, because the mean of its divisors is an integer number (5070067059).

Almost surely, 2^10140134117 is an apocalyptic number.

It is an amenable number.

10140134117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10140134117 is an equidigital number, since it uses as much as digits as its factorization.

10140134117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 10140134117 its reverse (71143104101), we get a palindrome (81283238218).

The spelling of 10140134117 in words is "ten billion, one hundred forty million, one hundred thirty-four thousand, one hundred seventeen".