Base | Representation |
---|---|
bin | 101111001110010001… |
… | …0100100010011101101 |
3 | 100200202110211222002211 |
4 | 1132130202210103231 |
5 | 3130142100230432 |
6 | 114330512050421 |
7 | 10220022332044 |
oct | 1363442442355 |
9 | 320673758084 |
10 | 101410555117 |
11 | 3a00a684033 |
12 | 177a2233a11 |
13 | 9741b15641 |
14 | 4ca051d55b |
15 | 2987eb6d47 |
hex | 179c8a44ed |
101410555117 has 2 divisors, whose sum is σ = 101410555118. Its totient is φ = 101410555116.
The previous prime is 101410555109. The next prime is 101410555201. The reversal of 101410555117 is 711555014101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74139665796 + 27270889321 = 272286^2 + 165139^2 .
It is a cyclic number.
It is not a de Polignac number, because 101410555117 - 23 = 101410555109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101470555117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50705277558 + 50705277559.
It is an arithmetic number, because the mean of its divisors is an integer number (50705277559).
Almost surely, 2101410555117 is an apocalyptic number.
It is an amenable number.
101410555117 is a deficient number, since it is larger than the sum of its proper divisors (1).
101410555117 is an equidigital number, since it uses as much as digits as its factorization.
101410555117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3500, while the sum is 31.
Adding to 101410555117 its reverse (711555014101), we get a palindrome (812965569218).
The spelling of 101410555117 in words is "one hundred one billion, four hundred ten million, five hundred fifty-five thousand, one hundred seventeen".
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