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1014113143 is a prime number
BaseRepresentation
bin111100011100100…
…010001101110111
32121200020021201001
4330130202031313
54034103110033
6244343544131
734062551041
oct7434421567
92550207631
101014113143
1148049323a
1224375b047
1313213bc64
1498982a91
155e06ce7d
hex3c722377

1014113143 has 2 divisors, whose sum is σ = 1014113144. Its totient is φ = 1014113142.

The previous prime is 1014113129. The next prime is 1014113159. The reversal of 1014113143 is 3413114101.

It is a weak prime.

It is an emirp because it is prime and its reverse (3413114101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1014113143 - 213 = 1014104951 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1014113143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1014111143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507056571 + 507056572.

It is an arithmetic number, because the mean of its divisors is an integer number (507056572).

Almost surely, 21014113143 is an apocalyptic number.

1014113143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1014113143 is an equidigital number, since it uses as much as digits as its factorization.

1014113143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 1014113143 is about 31845.1431618701. The cubic root of 1014113143 is about 1004.6824217062.

Adding to 1014113143 its reverse (3413114101), we get a palindrome (4427227244).

The spelling of 1014113143 in words is "one billion, fourteen million, one hundred thirteen thousand, one hundred forty-three".