Base | Representation |
---|---|
bin | 11101100000111110001… |
… | …11000010111001101111 |
3 | 10120221122202110022122022 |
4 | 32300133013002321233 |
5 | 113103421330104242 |
6 | 2053515315540355 |
7 | 133161122442443 |
oct | 16603707027157 |
9 | 3527582408568 |
10 | 1014134222447 |
11 | 36110136a475 |
12 | 1446675ba6bb |
13 | 7482b641088 |
14 | 3712769c823 |
15 | 1b5a755e0d2 |
hex | ec1f1c2e6f |
1014134222447 has 2 divisors, whose sum is σ = 1014134222448. Its totient is φ = 1014134222446.
The previous prime is 1014134222399. The next prime is 1014134222459. The reversal of 1014134222447 is 7442224314101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1014134222447 - 28 = 1014134222191 is a prime.
It is a super-2 number, since 2×10141342224472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1014134222477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507067111223 + 507067111224.
It is an arithmetic number, because the mean of its divisors is an integer number (507067111224).
Almost surely, 21014134222447 is an apocalyptic number.
1014134222447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1014134222447 is an equidigital number, since it uses as much as digits as its factorization.
1014134222447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43008, while the sum is 35.
Adding to 1014134222447 its reverse (7442224314101), we get a palindrome (8456358536548).
The spelling of 1014134222447 in words is "one trillion, fourteen billion, one hundred thirty-four million, two hundred twenty-two thousand, four hundred forty-seven".
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