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101420422013 is a prime number
BaseRepresentation
bin101111001110100100…
…0001101001101111101
3100200210011102020221102
41132131020031031331
53130202112001023
6114331503342445
710220202235361
oct1363510151575
9320704366842
10101420422013
113a015203199
12177a55b1a25
139743b8b741
144ca196b2a1
152988cb5628
hex179d20d37d

101420422013 has 2 divisors, whose sum is σ = 101420422014. Its totient is φ = 101420422012.

The previous prime is 101420422007. The next prime is 101420422039. The reversal of 101420422013 is 310224024101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86885226169 + 14535195844 = 294763^2 + 120562^2 .

It is a cyclic number.

It is not a de Polignac number, because 101420422013 - 24 = 101420421997 is a prime.

It is a super-2 number, since 2×1014204220132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101420422513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50710211006 + 50710211007.

It is an arithmetic number, because the mean of its divisors is an integer number (50710211007).

Almost surely, 2101420422013 is an apocalyptic number.

It is an amenable number.

101420422013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101420422013 is an equidigital number, since it uses as much as digits as its factorization.

101420422013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 101420422013 its reverse (310224024101), we get a palindrome (411644446114).

The spelling of 101420422013 in words is "one hundred one billion, four hundred twenty million, four hundred twenty-two thousand, thirteen".