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1014312065321 is a prime number
BaseRepresentation
bin11101100001010011011…
…01011101100100101001
310120222010011002200012102
432300221231131210221
5113104302342042241
62053545111423145
7133165412205002
oct16605155354451
93528104080172
101014312065321
11361192799455
121446b7084ab5
137485943b149
14371431541a9
151b5b7e8d39b
hexec29b5d929

1014312065321 has 2 divisors, whose sum is σ = 1014312065322. Its totient is φ = 1014312065320.

The previous prime is 1014312065287. The next prime is 1014312065323. The reversal of 1014312065321 is 1235602134101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 997841166400 + 16470898921 = 998920^2 + 128339^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1014312065321 is a prime.

Together with 1014312065323, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1014312065323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507156032660 + 507156032661.

It is an arithmetic number, because the mean of its divisors is an integer number (507156032661).

Almost surely, 21014312065321 is an apocalyptic number.

It is an amenable number.

1014312065321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1014312065321 is an equidigital number, since it uses as much as digits as its factorization.

1014312065321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 1014312065321 its reverse (1235602134101), we get a palindrome (2249914199422).

The spelling of 1014312065321 in words is "one trillion, fourteen billion, three hundred twelve million, sixty-five thousand, three hundred twenty-one".