10143135031 has 2 divisors, whose sum is σ = 10143135032. Its totient is φ = 10143135030.

The previous prime is 10143135011. The next prime is 10143135043. The reversal of 10143135031 is 13053134101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10143135031 - 2¹¹ = 10143132983 is a prime.

It is a super-2 number, since 2×10143135031² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10143134993 and 10143135011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10143135011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071567515 + 5071567516.

It is an arithmetic number, because the mean of its divisors is an integer number (5071567516).

Almost surely, 2^10143135031 is an apocalyptic number.

10143135031 is a deficient number, since it is larger than the sum of its proper divisors (1).

10143135031 is an equidigital number, since it uses as much as digits as its factorization.

10143135031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 10143135031 its reverse (13053134101), we get a palindrome (23196269132).

The spelling of 10143135031 in words is "ten billion, one hundred forty-three million, one hundred thirty-five thousand, thirty-one".