10143312102 has 128 divisors (see below), whose sum is σ = 28217548800. Its totient is φ = 2623860000.

The previous prime is 10143312061. The next prime is 10143312103. The reversal of 10143312102 is 20121334101.

10143312102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10143312103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1038799 + ... + 1048517.

It is an arithmetic number, because the mean of its divisors is an integer number (220449600).

Almost surely, 2^10143312102 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10143312102, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14108774400).

10143312102 is an abundant number, since it is smaller than the sum of its proper divisors (18074236698).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10143312102 is a wasteful number, since it uses less digits than its factorization.

10143312102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9999 (or 9993 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 10143312102 its reverse (20121334101), we get a palindrome (30264646203).

The spelling of 10143312102 in words is "ten billion, one hundred forty-three million, three hundred twelve thousand, one hundred two".