10143313234 has 4 divisors (see below), whose sum is σ = 15214969854. Its totient is φ = 5071656616.

The previous prime is 10143313139. The next prime is 10143313241. The reversal of 10143313234 is 43231334101.

10143313234 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 6813677025 + 3329636209 = 82545^2 + 57703^2 .

It is a junction number, because it is equal to n+sod(n) for n = 10143313199 and 10143313208.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2535828307 + ... + 2535828310.

Almost surely, 2^10143313234 is an apocalyptic number.

10143313234 is a deficient number, since it is larger than the sum of its proper divisors (5071656620).

10143313234 is an equidigital number, since it uses as much as digits as its factorization.

10143313234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5071656619.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 10143313234 its reverse (43231334101), we get a palindrome (53374647335).

The spelling of 10143313234 in words is "ten billion, one hundred forty-three million, three hundred thirteen thousand, two hundred thirty-four".