Base | Representation |
---|---|
bin | 1001001110011010110100… |
… | …0100000111011110010011 |
3 | 1022220200200111120211202202 |
4 | 2103212231010013132103 |
5 | 2312142010224322121 |
6 | 33323435534233415 |
7 | 2064554646446243 |
oct | 223465504073623 |
9 | 38820614524682 |
10 | 10143321323411 |
11 | 32608384a6641 |
12 | 1179a1595586b |
13 | 587684b57433 |
14 | 270d218c7b23 |
15 | 128cb752a40b |
hex | 939ad107793 |
10143321323411 has 2 divisors, whose sum is σ = 10143321323412. Its totient is φ = 10143321323410.
The previous prime is 10143321323357. The next prime is 10143321323413. The reversal of 10143321323411 is 11432312334101.
10143321323411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10143321323411 - 238 = 9868443416467 is a prime.
Together with 10143321323413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10143321323413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071660661705 + 5071660661706.
It is an arithmetic number, because the mean of its divisors is an integer number (5071660661706).
Almost surely, 210143321323411 is an apocalyptic number.
10143321323411 is a deficient number, since it is larger than the sum of its proper divisors (1).
10143321323411 is an equidigital number, since it uses as much as digits as its factorization.
10143321323411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 10143321323411 its reverse (11432312334101), we get a palindrome (21575633657512).
The spelling of 10143321323411 in words is "ten trillion, one hundred forty-three billion, three hundred twenty-one million, three hundred twenty-three thousand, four hundred eleven".
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