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10143412400021 is a prime number
BaseRepresentation
bin1001001110011011001001…
…1111100010111110010101
31022220200220211222000101112
42103212302133202332111
52312142202033300041
633323452550304405
72064560133544565
oct223466237427625
938820824860345
1010143412400021
11326088495286a
121179a40358105
1358769a995414
14270d2da34da5
15128cc051adeb
hex939b27e2f95

10143412400021 has 2 divisors, whose sum is σ = 10143412400022. Its totient is φ = 10143412400020.

The previous prime is 10143412399993. The next prime is 10143412400039. The reversal of 10143412400021 is 12000421434101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7325331706225 + 2818080693796 = 2706535^2 + 1678714^2 .

It is a cyclic number.

It is not a de Polignac number, because 10143412400021 - 230 = 10142338658197 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10143412400021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10143412400321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071706200010 + 5071706200011.

It is an arithmetic number, because the mean of its divisors is an integer number (5071706200011).

Almost surely, 210143412400021 is an apocalyptic number.

It is an amenable number.

10143412400021 is a deficient number, since it is larger than the sum of its proper divisors (1).

10143412400021 is an equidigital number, since it uses as much as digits as its factorization.

10143412400021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 10143412400021 its reverse (12000421434101), we get a palindrome (22143833834122).

The spelling of 10143412400021 in words is "ten trillion, one hundred forty-three billion, four hundred twelve million, four hundred thousand, twenty-one".