Base | Representation |
---|---|
bin | 11101100001010110111… |
… | …00111110111110011100 |
3 | 10120222012012002221210220 |
4 | 32300223130332332130 |
5 | 113104332333100444 |
6 | 2053552034201340 |
7 | 133166215535445 |
oct | 16605334767634 |
9 | 3528165087726 |
10 | 1014341300124 |
11 | 3611a8246a49 |
12 | 144704a23250 |
13 | 74862505a49 |
14 | 37146da42cc |
15 | 1b5ba815619 |
hex | ec2b73ef9c |
1014341300124 has 48 divisors (see below), whose sum is σ = 2373761617920. Its totient is φ = 337119939520.
The previous prime is 1014341300039. The next prime is 1014341300143. The reversal of 1014341300124 is 4210031434101.
It is a super-4 number, since 4×10143413001244 (a number of 49 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1014341300094 and 1014341300103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6713677 + ... + 6863099.
It is an arithmetic number, because the mean of its divisors is an integer number (49453367040).
Almost surely, 21014341300124 is an apocalyptic number.
It is an amenable number.
1014341300124 is an abundant number, since it is smaller than the sum of its proper divisors (1359420317796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1014341300124 is a wasteful number, since it uses less digits than its factorization.
1014341300124 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151090 (or 151088 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1014341300124 its reverse (4210031434101), we get a palindrome (5224372734225).
The spelling of 1014341300124 in words is "one trillion, fourteen billion, three hundred forty-one million, three hundred thousand, one hundred twenty-four".
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