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10143424433 is a prime number
BaseRepresentation
bin10010111001001100…
…00101111110110001
3222011220122100110102
421130212011332301
5131233204040213
64354304442145
7506235453662
oct113446057661
928156570412
1010143424433
1143357759aa
121b71019355
13c586263bc
146c3219369
153e578e158
hex25c985fb1

10143424433 has 2 divisors, whose sum is σ = 10143424434. Its totient is φ = 10143424432.

The previous prime is 10143424411. The next prime is 10143424441. The reversal of 10143424433 is 33442434101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5368199824 + 4775224609 = 73268^2 + 69103^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10143424433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10143424396 and 10143424405.

It is not a weakly prime, because it can be changed into another prime (10143484433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071712216 + 5071712217.

It is an arithmetic number, because the mean of its divisors is an integer number (5071712217).

Almost surely, 210143424433 is an apocalyptic number.

It is an amenable number.

10143424433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10143424433 is an equidigital number, since it uses as much as digits as its factorization.

10143424433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 10143424433 its reverse (33442434101), we get a palindrome (43585858534).

The spelling of 10143424433 in words is "ten billion, one hundred forty-three million, four hundred twenty-four thousand, four hundred thirty-three".