Base | Representation |
---|---|
bin | 11101100001010111000… |
… | …11011110100011011011 |
3 | 10120222012022022102210121 |
4 | 32300223203132203123 |
5 | 113104333302033311 |
6 | 2053552134454111 |
7 | 133166236155241 |
oct | 16605343364333 |
9 | 3528168272717 |
10 | 1014343002331 |
11 | 3611a91a992a |
12 | 144705504337 |
13 | 74862980779 |
14 | 371472c8791 |
15 | 1b5baa4eb71 |
hex | ec2b8de8db |
1014343002331 has 2 divisors, whose sum is σ = 1014343002332. Its totient is φ = 1014343002330.
The previous prime is 1014343002319. The next prime is 1014343002347. The reversal of 1014343002331 is 1332003434101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1014343002331 - 217 = 1014342871259 is a prime.
It is a super-2 number, since 2×10143430023312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1014343002296 and 1014343002305.
It is not a weakly prime, because it can be changed into another prime (1014343002391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507171501165 + 507171501166.
It is an arithmetic number, because the mean of its divisors is an integer number (507171501166).
Almost surely, 21014343002331 is an apocalyptic number.
1014343002331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1014343002331 is an equidigital number, since it uses as much as digits as its factorization.
1014343002331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1014343002331 its reverse (1332003434101), we get a palindrome (2346346436432).
The spelling of 1014343002331 in words is "one trillion, fourteen billion, three hundred forty-three million, two thousand, three hundred thirty-one".
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