Base | Representation |
---|---|
bin | 101111001110111110… |
… | …1001100100110101011 |
3 | 100200211010112222222021 |
4 | 1132131331030212223 |
5 | 3130214141010011 |
6 | 114333121205311 |
7 | 10220431302304 |
oct | 1363575144653 |
9 | 320733488867 |
10 | 101434313131 |
11 | 3a022030858 |
12 | 177aa190837 |
13 | 9746a13438 |
14 | 4ca37457ab |
15 | 298a10b471 |
hex | 179df4c9ab |
101434313131 has 2 divisors, whose sum is σ = 101434313132. Its totient is φ = 101434313130.
The previous prime is 101434313093. The next prime is 101434313249. The reversal of 101434313131 is 131313434101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101434313131 - 29 = 101434312619 is a prime.
It is a super-2 number, since 2×1014343131312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 101434313096 and 101434313105.
It is not a weakly prime, because it can be changed into another prime (101434383131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50717156565 + 50717156566.
It is an arithmetic number, because the mean of its divisors is an integer number (50717156566).
Almost surely, 2101434313131 is an apocalyptic number.
101434313131 is a deficient number, since it is larger than the sum of its proper divisors (1).
101434313131 is an equidigital number, since it uses as much as digits as its factorization.
101434313131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 101434313131 its reverse (131313434101), we get a palindrome (232747747232).
The spelling of 101434313131 in words is "one hundred one billion, four hundred thirty-four million, three hundred thirteen thousand, one hundred thirty-one".
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