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10143451130 = 251014345113
BaseRepresentation
bin10010111001001100…
…01100011111111010
3222011220200201002012
421130212030133322
5131233210414010
64354305205522
7506235624551
oct113446143772
928156621065
1010143451130
114335793a6a
121b710308a2
13c586355b7
146c3224d98
153e5797005
hex25c98c7fa

10143451130 has 8 divisors (see below), whose sum is σ = 18258212052. Its totient is φ = 4057380448.

The previous prime is 10143451121. The next prime is 10143451181. The reversal of 10143451130 is 3115434101.

It is a happy number.

It can be written as a sum of positive squares in 2 ways, for example, as 9520100041 + 623351089 = 97571^2 + 24967^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 10143451096 and 10143451105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 507172547 + ... + 507172566.

Almost surely, 210143451130 is an apocalyptic number.

10143451130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

10143451130 is a deficient number, since it is larger than the sum of its proper divisors (8114760922).

10143451130 is a wasteful number, since it uses less digits than its factorization.

10143451130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1014345120.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 10143451130 its reverse (3115434101), we get a palindrome (13258885231).

The spelling of 10143451130 in words is "ten billion, one hundred forty-three million, four hundred fifty-one thousand, one hundred thirty".

Divisors: 1 2 5 10 1014345113 2028690226 5071725565 10143451130