Base | Representation |
---|---|
bin | 10010111001010000… |
… | …11101000110011011 |
3 | 222011221210210112211 |
4 | 21130220131012123 |
5 | 131233333342134 |
6 | 4354330015551 |
7 | 506243642416 |
oct | 113450350633 |
9 | 28157723484 |
10 | 10144043419 |
11 | 4336058a64 |
12 | 1b712775b7 |
13 | c587b2073 |
14 | 6c333ab7d |
15 | 3e5862764 |
hex | 25ca1d19b |
10144043419 has 2 divisors, whose sum is σ = 10144043420. Its totient is φ = 10144043418.
The previous prime is 10144043407. The next prime is 10144043431. The reversal of 10144043419 is 91434044101.
10144043419 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (10144043407) and next prime (10144043431).
It is a cyclic number.
It is not a de Polignac number, because 10144043419 - 25 = 10144043387 is a prime.
It is a super-2 number, since 2×101440434192 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10144041419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072021709 + 5072021710.
It is an arithmetic number, because the mean of its divisors is an integer number (5072021710).
Almost surely, 210144043419 is an apocalyptic number.
10144043419 is a deficient number, since it is larger than the sum of its proper divisors (1).
10144043419 is an equidigital number, since it uses as much as digits as its factorization.
10144043419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 10144043419 in words is "ten billion, one hundred forty-four million, forty-three thousand, four hundred nineteen".
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