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10144044331 is a prime number
BaseRepresentation
bin10010111001010000…
…11101010100101011
3222011221210211210121
421130220131110223
5131233333404311
64354330024111
7506243645161
oct113450352453
928157724717
1010144044331
114336059713
121b71278037
13c587b25c5
146c333b231
153e5862b71
hex25ca1d52b

10144044331 has 2 divisors, whose sum is σ = 10144044332. Its totient is φ = 10144044330.

The previous prime is 10144044307. The next prime is 10144044359. The reversal of 10144044331 is 13344044101.

10144044331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10144044331 - 213 = 10144036139 is a prime.

It is a super-2 number, since 2×101440443312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10144044296 and 10144044305.

It is not a weakly prime, because it can be changed into another prime (10144041331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072022165 + 5072022166.

It is an arithmetic number, because the mean of its divisors is an integer number (5072022166).

Almost surely, 210144044331 is an apocalyptic number.

10144044331 is a deficient number, since it is larger than the sum of its proper divisors (1).

10144044331 is an equidigital number, since it uses as much as digits as its factorization.

10144044331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 10144044331 its reverse (13344044101), we get a palindrome (23488088432).

The spelling of 10144044331 in words is "ten billion, one hundred forty-four million, forty-four thousand, three hundred thirty-one".