10144323127 has 2 divisors, whose sum is σ = 10144323128. Its totient is φ = 10144323126.

The previous prime is 10144323109. The next prime is 10144323131. The reversal of 10144323127 is 72132344101.

10144323127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (72132344101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10144323127 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10144323095 and 10144323104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10144323727) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072161563 + 5072161564.

It is an arithmetic number, because the mean of its divisors is an integer number (5072161564).

Almost surely, 2^10144323127 is an apocalyptic number.

10144323127 is a deficient number, since it is larger than the sum of its proper divisors (1).

10144323127 is an equidigital number, since it uses as much as digits as its factorization.

10144323127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 10144323127 its reverse (72132344101), we get a palindrome (82276667228).

The spelling of 10144323127 in words is "ten billion, one hundred forty-four million, three hundred twenty-three thousand, one hundred twenty-seven".