Base | Representation |
---|---|
bin | 10010111001010011… |
… | …00110000000001111 |
3 | 222011222100222011112 |
4 | 21130221212000033 |
5 | 131233422421111 |
6 | 4354340242235 |
7 | 506246325125 |
oct | 113451460017 |
9 | 28158328145 |
10 | 10144342031 |
11 | 433624234a |
12 | 1b713a037b |
13 | c58887c65 |
14 | 6c33b7915 |
15 | 3e58c0e8b |
hex | 25ca6600f |
10144342031 has 2 divisors, whose sum is σ = 10144342032. Its totient is φ = 10144342030.
The previous prime is 10144341973. The next prime is 10144342063. The reversal of 10144342031 is 13024344101.
It is a strong prime.
It is an emirp because it is prime and its reverse (13024344101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10144342031 - 26 = 10144341967 is a prime.
It is a super-2 number, since 2×101443420312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10144341988 and 10144342006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10144348031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072171015 + 5072171016.
It is an arithmetic number, because the mean of its divisors is an integer number (5072171016).
Almost surely, 210144342031 is an apocalyptic number.
10144342031 is a deficient number, since it is larger than the sum of its proper divisors (1).
10144342031 is an equidigital number, since it uses as much as digits as its factorization.
10144342031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 10144342031 its reverse (13024344101), we get a palindrome (23168686132).
The spelling of 10144342031 in words is "ten billion, one hundred forty-four million, three hundred forty-two thousand, thirty-one".
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