Base | Representation |
---|---|
bin | 11101100001100010110… |
… | …10011101100010111111 |
3 | 10120222110011021120212202 |
4 | 32300301122131202333 |
5 | 113110033433132312 |
6 | 2054010005422115 |
7 | 133201541536634 |
oct | 16606132354277 |
9 | 3528404246782 |
10 | 1014441302207 |
11 | 361249739aa3 |
12 | 14473240a93b |
13 | 7487a14a488 |
14 | 3715639618b |
15 | 1b5c44ba9c2 |
hex | ec3169d8bf |
1014441302207 has 2 divisors, whose sum is σ = 1014441302208. Its totient is φ = 1014441302206.
The previous prime is 1014441302117. The next prime is 1014441302227. The reversal of 1014441302207 is 7022031444101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1014441302207 - 224 = 1014424524991 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1014441302207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1014441302227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507220651103 + 507220651104.
It is an arithmetic number, because the mean of its divisors is an integer number (507220651104).
Almost surely, 21014441302207 is an apocalyptic number.
1014441302207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1014441302207 is an equidigital number, since it uses as much as digits as its factorization.
1014441302207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 29.
Adding to 1014441302207 its reverse (7022031444101), we get a palindrome (8036472746308).
The spelling of 1014441302207 in words is "one trillion, fourteen billion, four hundred forty-one million, three hundred two thousand, two hundred seven".
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