Base | Representation |
---|---|
bin | 10010111001010011… |
… | …11001000010111111 |
3 | 222011222111221011102 |
4 | 21130221321002333 |
5 | 131233432420111 |
6 | 4354342043315 |
7 | 506250101414 |
oct | 113451710277 |
9 | 28158457142 |
10 | 10144420031 |
11 | 4336295a09 |
12 | 1b7141953b |
13 | c588b4605 |
14 | 6c33d810b |
15 | 3e58d913b |
hex | 25ca790bf |
10144420031 has 2 divisors, whose sum is σ = 10144420032. Its totient is φ = 10144420030.
The previous prime is 10144420009. The next prime is 10144420037. The reversal of 10144420031 is 13002444101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10144420031 - 230 = 9070678207 is a prime.
It is a super-2 number, since 2×101444200312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10144419985 and 10144420012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10144420037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072210015 + 5072210016.
It is an arithmetic number, because the mean of its divisors is an integer number (5072210016).
Almost surely, 210144420031 is an apocalyptic number.
10144420031 is a deficient number, since it is larger than the sum of its proper divisors (1).
10144420031 is an equidigital number, since it uses as much as digits as its factorization.
10144420031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 10144420031 its reverse (13002444101), we get a palindrome (23146864132).
The spelling of 10144420031 in words is "ten billion, one hundred forty-four million, four hundred twenty thousand, thirty-one".
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