1014443031132 has 24 divisors (see below), whose sum is σ = 2630037488400. Its totient is φ = 338147677008.

The previous prime is 1014443031079. The next prime is 1014443031137. The reversal of 1014443031132 is 2311303444101.

1014443031132 is a `hidden beast` number, since 101 + 4 + 443 + 0 + 3 + 113 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 1014443031096 and 1014443031105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1014443031137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4696495407 + ... + 4696495622.

It is an arithmetic number, because the mean of its divisors is an integer number (109584895350).

Almost surely, 2^{1014443031132} is an apocalyptic number.

1014443031132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1014443031132 is an abundant number, since it is smaller than the sum of its proper divisors (1615594457268).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1014443031132 is a wasteful number, since it uses less digits than its factorization.

1014443031132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9392991042 (or 9392991034 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 1014443031132 its reverse (2311303444101), we get a palindrome (3325746475233).

The spelling of 1014443031132 in words is "one trillion, fourteen billion, four hundred forty-three million, thirty-one thousand, one hundred thirty-two".