Base | Representation |
---|---|
bin | 10010111001010100… |
… | …00001111011010011 |
3 | 222011222120210001112 |
4 | 21130222001323103 |
5 | 131233440101103 |
6 | 4354342523535 |
7 | 506250312434 |
oct | 113452017323 |
9 | 28158523045 |
10 | 10144456403 |
11 | 4336310274 |
12 | 1b714365ab |
13 | c588c8033 |
14 | 6c340748b |
15 | 3e58e4cd8 |
hex | 25ca81ed3 |
10144456403 has 2 divisors, whose sum is σ = 10144456404. Its totient is φ = 10144456402.
The previous prime is 10144456397. The next prime is 10144456417. The reversal of 10144456403 is 30465444101.
10144456403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10144456403 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10144456403.
It is not a weakly prime, because it can be changed into another prime (10144456493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072228201 + 5072228202.
It is an arithmetic number, because the mean of its divisors is an integer number (5072228202).
Almost surely, 210144456403 is an apocalyptic number.
10144456403 is a deficient number, since it is larger than the sum of its proper divisors (1).
10144456403 is an equidigital number, since it uses as much as digits as its factorization.
10144456403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 32.
The spelling of 10144456403 in words is "ten billion, one hundred forty-four million, four hundred fifty-six thousand, four hundred three".
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