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10145241433573 is a prime number
BaseRepresentation
bin1001001110100001111110…
…0000110000010111100101
31022220212122022121112201221
42103220133200300113211
52312204423301333243
633324354245020341
72064653353224121
oct223503740602745
938825568545657
1010145241433573
113261633337844
12117a2709b46b1
135878cc8ac5ac
14271064908581
15128d7adabbed
hex93a1f8305e5

10145241433573 has 2 divisors, whose sum is σ = 10145241433574. Its totient is φ = 10145241433572.

The previous prime is 10145241433489. The next prime is 10145241433597. The reversal of 10145241433573 is 37533414254101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9788094159649 + 357147273924 = 3128593^2 + 597618^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10145241433573 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10145241433073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072620716786 + 5072620716787.

It is an arithmetic number, because the mean of its divisors is an integer number (5072620716787).

Almost surely, 210145241433573 is an apocalyptic number.

It is an amenable number.

10145241433573 is a deficient number, since it is larger than the sum of its proper divisors (1).

10145241433573 is an equidigital number, since it uses as much as digits as its factorization.

10145241433573 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 604800, while the sum is 43.

Adding to 10145241433573 its reverse (37533414254101), we get a palindrome (47678655687674).

The spelling of 10145241433573 in words is "ten trillion, one hundred forty-five billion, two hundred forty-one million, four hundred thirty-three thousand, five hundred seventy-three".