Base | Representation |
---|---|
bin | 101111010000011100… |
… | …0001101110110001011 |
3 | 100200221112210210000122 |
4 | 1132200320031312023 |
5 | 3130314213323042 |
6 | 114342032053455 |
7 | 10221565102301 |
oct | 1364070156613 |
9 | 320845723018 |
10 | 101483339147 |
11 | 3a047776823 |
12 | 1780269428b |
13 | 9753c1a408 |
14 | 4caa068271 |
15 | 298e5927d2 |
hex | 17a0e0dd8b |
101483339147 has 2 divisors, whose sum is σ = 101483339148. Its totient is φ = 101483339146.
The previous prime is 101483339141. The next prime is 101483339203. The reversal of 101483339147 is 741933384101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101483339147 - 216 = 101483273611 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101483339098 and 101483339107.
It is not a weakly prime, because it can be changed into another prime (101483339141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50741669573 + 50741669574.
It is an arithmetic number, because the mean of its divisors is an integer number (50741669574).
Almost surely, 2101483339147 is an apocalyptic number.
101483339147 is a deficient number, since it is larger than the sum of its proper divisors (1).
101483339147 is an equidigital number, since it uses as much as digits as its factorization.
101483339147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 217728, while the sum is 44.
The spelling of 101483339147 in words is "one hundred one billion, four hundred eighty-three million, three hundred thirty-nine thousand, one hundred forty-seven".
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