101483339141 has 2 divisors, whose sum is σ = 101483339142. Its totient is φ = 101483339140.

The previous prime is 101483339137. The next prime is 101483339147. The reversal of 101483339141 is 141933384101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92464038241 + 9019300900 = 304079^2 + 94970^2 .

It is a cyclic number.

It is not a de Polignac number, because 101483339141 - 2² = 101483339137 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101483339095 and 101483339104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101483339147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50741669570 + 50741669571.

It is an arithmetic number, because the mean of its divisors is an integer number (50741669571).

Almost surely, 2^101483339141 is an apocalyptic number.

It is an amenable number.

101483339141 is a deficient number, since it is larger than the sum of its proper divisors (1).

101483339141 is an equidigital number, since it uses as much as digits as its factorization.

101483339141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 38.

The spelling of 101483339141 in words is "one hundred one billion, four hundred eighty-three million, three hundred thirty-nine thousand, one hundred forty-one".