1015055504941 has 2 divisors, whose sum is σ = 1015055504942. Its totient is φ = 1015055504940.

The previous prime is 1015055504929. The next prime is 1015055505049. The reversal of 1015055504941 is 1494055505101.

1015055504941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 647777083716 + 367278421225 = 804846^2 + 606035^2 .

It is an emirp because it is prime and its reverse (1494055505101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1015055504941 - 2⁵ = 1015055504909 is a prime.

It is a super-2 number, since 2×1015055504941² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1015055504894 and 1015055504903.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1015055504041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507527752470 + 507527752471.

It is an arithmetic number, because the mean of its divisors is an integer number (507527752471).

Almost surely, 2^{1015055504941} is an apocalyptic number.

It is an amenable number.

1015055504941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1015055504941 is an equidigital number, since it uses as much as digits as its factorization.

1015055504941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90000, while the sum is 40.

The spelling of 1015055504941 in words is "one trillion, fifteen billion, fifty-five million, five hundred four thousand, nine hundred forty-one".