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10153632497 is a prime number
BaseRepresentation
bin10010111010011010…
…00010001011110001
3222012121211222021212
421131031002023301
5131243312214442
64355311325505
7506421311051
oct113515021361
928177758255
1010153632497
114340508418
121b74520895
13c5a78b888
146c4715561
153e6608a82
hex25d3422f1

10153632497 has 2 divisors, whose sum is σ = 10153632498. Its totient is φ = 10153632496.

The previous prime is 10153632481. The next prime is 10153632499. The reversal of 10153632497 is 79423635101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5386972816 + 4766659681 = 73396^2 + 69041^2 .

It is an emirp because it is prime and its reverse (79423635101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10153632497 - 24 = 10153632481 is a prime.

Together with 10153632499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10153632499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5076816248 + 5076816249.

It is an arithmetic number, because the mean of its divisors is an integer number (5076816249).

Almost surely, 210153632497 is an apocalyptic number.

It is an amenable number.

10153632497 is a deficient number, since it is larger than the sum of its proper divisors (1).

10153632497 is an equidigital number, since it uses as much as digits as its factorization.

10153632497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 41.

The spelling of 10153632497 in words is "ten billion, one hundred fifty-three million, six hundred thirty-two thousand, four hundred ninety-seven".