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10154050635433 is a prime number
BaseRepresentation
bin1001001111000010110010…
…0101001100011010101001
31022221201101020200100220111
42103300230211030122221
52312330443430313213
633332412332454321
72065414561214305
oct223605445143251
938851336610814
1010154050635433
113265343960561
12117bb0b01a3a1
135886a4977a83
1427165c854d05
151291e444aa3d
hex93c2c94c6a9

10154050635433 has 2 divisors, whose sum is σ = 10154050635434. Its totient is φ = 10154050635432.

The previous prime is 10154050635403. The next prime is 10154050635473. The reversal of 10154050635433 is 33453605045101.

It is an a-pointer prime, because the next prime (10154050635473) can be obtained adding 10154050635433 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9508539622464 + 645511012969 = 3083592^2 + 803437^2 .

It is a cyclic number.

It is not a de Polignac number, because 10154050635433 - 213 = 10154050627241 is a prime.

It is a super-3 number, since 3×101540506354333 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (10154050635403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5077025317716 + 5077025317717.

It is an arithmetic number, because the mean of its divisors is an integer number (5077025317717).

Almost surely, 210154050635433 is an apocalyptic number.

It is an amenable number.

10154050635433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10154050635433 is an equidigital number, since it uses as much as digits as its factorization.

10154050635433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324000, while the sum is 40.

The spelling of 10154050635433 in words is "ten trillion, one hundred fifty-four billion, fifty million, six hundred thirty-five thousand, four hundred thirty-three".