Base | Representation |
---|---|
bin | 10010111010100000… |
… | …10000110011001001 |
3 | 222012200102222012011 |
4 | 21131100100303021 |
5 | 131244021310133 |
6 | 4355341415521 |
7 | 506431434304 |
oct | 113520206311 |
9 | 28180388164 |
10 | 10154478793 |
11 | 4340a36238 |
12 | 1b7486a5a1 |
13 | c5a9c6b44 |
14 | 6c4895b3b |
15 | 3e67246cd |
hex | 25d410cc9 |
10154478793 has 2 divisors, whose sum is σ = 10154478794. Its totient is φ = 10154478792.
The previous prime is 10154478791. The next prime is 10154478857. The reversal of 10154478793 is 39787445101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8863657609 + 1290821184 = 94147^2 + 35928^2 .
It is a cyclic number.
It is not a de Polignac number, because 10154478793 - 21 = 10154478791 is a prime.
It is a super-2 number, since 2×101544787932 (a number of 21 digits) contains 22 as substring.
Together with 10154478791, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10154478791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5077239396 + 5077239397.
It is an arithmetic number, because the mean of its divisors is an integer number (5077239397).
Almost surely, 210154478793 is an apocalyptic number.
It is an amenable number.
10154478793 is a deficient number, since it is larger than the sum of its proper divisors (1).
10154478793 is an equidigital number, since it uses as much as digits as its factorization.
10154478793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 846720, while the sum is 49.
The spelling of 10154478793 in words is "ten billion, one hundred fifty-four million, four hundred seventy-eight thousand, seven hundred ninety-three".
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