Base | Representation |
---|---|
bin | 101111010010100100… |
… | …1110100001011110101 |
3 | 100201010112202122120211 |
4 | 1132211021310023311 |
5 | 3130441043431433 |
6 | 114353113225421 |
7 | 10223425531324 |
oct | 1364511641365 |
9 | 321115678524 |
10 | 101555061493 |
11 | 3a084203896 |
12 | 17822702271 |
13 | 9765a3cb82 |
14 | 4cb57b80bb |
15 | 2995a0d8cd |
hex | 17a52742f5 |
101555061493 has 2 divisors, whose sum is σ = 101555061494. Its totient is φ = 101555061492.
The previous prime is 101555061469. The next prime is 101555061527. The reversal of 101555061493 is 394160555101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 69993051844 + 31562009649 = 264562^2 + 177657^2 .
It is a cyclic number.
It is not a de Polignac number, because 101555061493 - 221 = 101552964341 is a prime.
It is a super-2 number, since 2×1015550614932 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101555061463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50777530746 + 50777530747.
It is an arithmetic number, because the mean of its divisors is an integer number (50777530747).
Almost surely, 2101555061493 is an apocalyptic number.
It is an amenable number.
101555061493 is a deficient number, since it is larger than the sum of its proper divisors (1).
101555061493 is an equidigital number, since it uses as much as digits as its factorization.
101555061493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 40.
The spelling of 101555061493 in words is "one hundred one billion, five hundred fifty-five million, sixty-one thousand, four hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •