Base | Representation |
---|---|
bin | 10111000110100011001010… |
… | …011101111100011010101011 |
3 | 111022202100122010102201021121 |
4 | 113012203022131330122223 |
5 | 101304144313124421301 |
6 | 1000032431452120111 |
7 | 30254505111216601 |
oct | 2706431235743253 |
9 | 438670563381247 |
10 | 101605143201451 |
11 | 2a413554550a7a |
12 | b48b910a66037 |
13 | 4490429789146 |
14 | 1b13a025d9871 |
15 | bb2eb26953a1 |
hex | 5c68ca77c6ab |
101605143201451 has 2 divisors, whose sum is σ = 101605143201452. Its totient is φ = 101605143201450.
The previous prime is 101605143201431. The next prime is 101605143201493. The reversal of 101605143201451 is 154102341506101.
It is a weak prime.
It is an emirp because it is prime and its reverse (154102341506101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101605143201451 - 27 = 101605143201323 is a prime.
It is not a weakly prime, because it can be changed into another prime (101605143201431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50802571600725 + 50802571600726.
It is an arithmetic number, because the mean of its divisors is an integer number (50802571600726).
Almost surely, 2101605143201451 is an apocalyptic number.
101605143201451 is a deficient number, since it is larger than the sum of its proper divisors (1).
101605143201451 is an equidigital number, since it uses as much as digits as its factorization.
101605143201451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 34.
Adding to 101605143201451 its reverse (154102341506101), we get a palindrome (255707484707552).
The spelling of 101605143201451 in words is "one hundred one trillion, six hundred five billion, one hundred forty-three million, two hundred one thousand, four hundred fifty-one".
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