10164053113 has 2 divisors, whose sum is σ = 10164053114. Its totient is φ = 10164053112.

The previous prime is 10164053077. The next prime is 10164053129. The reversal of 10164053113 is 31135046101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9391935744 + 772117369 = 96912^2 + 27787^2 .

It is an emirp because it is prime and its reverse (31135046101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10164053113 is a prime.

It is not a weakly prime, because it can be changed into another prime (10164053183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5082026556 + 5082026557.

It is an arithmetic number, because the mean of its divisors is an integer number (5082026557).

Almost surely, 2^10164053113 is an apocalyptic number.

It is an amenable number.

10164053113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10164053113 is an equidigital number, since it uses as much as digits as its factorization.

10164053113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 10164053113 its reverse (31135046101), we get a palindrome (41299099214).

The spelling of 10164053113 in words is "ten billion, one hundred sixty-four million, fifty-three thousand, one hundred thirteen".