Base | Representation |
---|---|
bin | 11101100101011001110… |
… | …00000001111111101001 |
3 | 10121011210111220000120122 |
4 | 32302230320001333221 |
5 | 113123304214314431 |
6 | 2054551321533025 |
7 | 133304062654253 |
oct | 16625470017751 |
9 | 3534714800518 |
10 | 1016512651241 |
11 | 3621119891aa |
12 | 145010044175 |
13 | 74b1a3163a9 |
14 | 372b1504cd3 |
15 | 1b696273a7b |
hex | ecace01fe9 |
1016512651241 has 2 divisors, whose sum is σ = 1016512651242. Its totient is φ = 1016512651240.
The previous prime is 1016512651237. The next prime is 1016512651243. The reversal of 1016512651241 is 1421562156101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 726526093225 + 289986558016 = 852365^2 + 538504^2 .
It is a cyclic number.
It is not a de Polignac number, because 1016512651241 - 22 = 1016512651237 is a prime.
Together with 1016512651243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1016512651243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 508256325620 + 508256325621.
It is an arithmetic number, because the mean of its divisors is an integer number (508256325621).
Almost surely, 21016512651241 is an apocalyptic number.
It is an amenable number.
1016512651241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1016512651241 is an equidigital number, since it uses as much as digits as its factorization.
1016512651241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 35.
The spelling of 1016512651241 in words is "one trillion, sixteen billion, five hundred twelve million, six hundred fifty-one thousand, two hundred forty-one".
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