Base | Representation |
---|---|
bin | 10010111011110011… |
… | …11101101010000001 |
3 | 222020110000100120201 |
4 | 21131321331222001 |
5 | 131304321113213 |
6 | 4400412005201 |
7 | 506623364053 |
oct | 113571755201 |
9 | 28213010521 |
10 | 10165410433 |
11 | 4347122352 |
12 | 1b78460801 |
13 | c60053779 |
14 | 6c60dd8d3 |
15 | 3e76836dd |
hex | 25de7da81 |
10165410433 has 2 divisors, whose sum is σ = 10165410434. Its totient is φ = 10165410432.
The previous prime is 10165410427. The next prime is 10165410439. The reversal of 10165410433 is 33401456101.
It is a balanced prime because it is at equal distance from previous prime (10165410427) and next prime (10165410439).
It can be written as a sum of positive squares in only one way, i.e., 6123375504 + 4042034929 = 78252^2 + 63577^2 .
It is a cyclic number.
It is not a de Polignac number, because 10165410433 - 213 = 10165402241 is a prime.
It is not a weakly prime, because it can be changed into another prime (10165410439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5082705216 + 5082705217.
It is an arithmetic number, because the mean of its divisors is an integer number (5082705217).
Almost surely, 210165410433 is an apocalyptic number.
It is an amenable number.
10165410433 is a deficient number, since it is larger than the sum of its proper divisors (1).
10165410433 is an equidigital number, since it uses as much as digits as its factorization.
10165410433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 10165410433 its reverse (33401456101), we get a palindrome (43566866534).
The spelling of 10165410433 in words is "ten billion, one hundred sixty-five million, four hundred ten thousand, four hundred thirty-three".
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