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1017741130753 is a prime number
BaseRepresentation
bin11101100111101100001…
…10010011110000000001
310121021222010111020122211
432303312012103300001
5113133313212141003
62055313244302121
7133346400606214
oct16636606236001
93537863436584
101017741130753
11362692377026
121452b3541941
1374c8499c749
143738a72977b
151b71903796d
hexecf6193c01

1017741130753 has 2 divisors, whose sum is σ = 1017741130754. Its totient is φ = 1017741130752.

The previous prime is 1017741130751. The next prime is 1017741130781. The reversal of 1017741130753 is 3570311477101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 975893064129 + 41848066624 = 987873^2 + 204568^2 .

It is a cyclic number.

It is not a de Polignac number, because 1017741130753 - 21 = 1017741130751 is a prime.

It is a super-3 number, since 3×10177411307533 (a number of 37 digits) contains 333 as substring.

Together with 1017741130751, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1017741130751) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 508870565376 + 508870565377.

It is an arithmetic number, because the mean of its divisors is an integer number (508870565377).

Almost surely, 21017741130753 is an apocalyptic number.

It is an amenable number.

1017741130753 is a deficient number, since it is larger than the sum of its proper divisors (1).

1017741130753 is an equidigital number, since it uses as much as digits as its factorization.

1017741130753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 61740, while the sum is 40.

The spelling of 1017741130753 in words is "one trillion, seventeen billion, seven hundred forty-one million, one hundred thirty thousand, seven hundred fifty-three".