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101842470313 is a prime number
BaseRepresentation
bin101111011011001001…
…0001100010110101001
3100201212120120112100221
41132312102030112221
53132033133022223
6114441421330041
710233515500033
oct1366622142651
9321776515327
10101842470313
113a211468341
12178a2a06921
1397b044c86c
144d01a30c53
1529b0d81b5d
hex17b648c5a9

101842470313 has 2 divisors, whose sum is σ = 101842470314. Its totient is φ = 101842470312.

The previous prime is 101842470307. The next prime is 101842470329. The reversal of 101842470313 is 313074248101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 64164942864 + 37677527449 = 253308^2 + 194107^2 .

It is a cyclic number.

It is not a de Polignac number, because 101842470313 - 25 = 101842470281 is a prime.

It is not a weakly prime, because it can be changed into another prime (101842470343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50921235156 + 50921235157.

It is an arithmetic number, because the mean of its divisors is an integer number (50921235157).

Almost surely, 2101842470313 is an apocalyptic number.

It is an amenable number.

101842470313 is a deficient number, since it is larger than the sum of its proper divisors (1).

101842470313 is an equidigital number, since it uses as much as digits as its factorization.

101842470313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 34.

The spelling of 101842470313 in words is "one hundred one billion, eight hundred forty-two million, four hundred seventy thousand, three hundred thirteen".